Assuming:-
Brick size = 9”x4.5”x3”
Thickness of mortar = 0.39”
Brick size with mortar= (9+0.39)x(4.5+0.39)x(3+0.39)
=9.39”x4.89”x3.39”
Thickness of wall = 4.5”
No. of bricks = Volume of brickwork/ Volume of 1 brick with mortar
Volume of 1 Brick = (9/12)x(4.5/12)x(3/12)=0.75’x0.375’x0.25’ = 0.070 CFT
Volume of 1 Brick with mortar = 0.783’x0.408’x0.283’=0.090 CFT.
Volume of Brickwork = 10’ x 6’ x 0.375’ = 22.5 Cubic Foot (CFT)
No. of bricks = Volume of brickwork/ Volume of 1 brick with mortar
∴ No. of bricks = 22.5 CFT/ 0.090 CFT
= 250 No’s
Brick wastage à 5 to 10 %
Consider 5% brick wastage,
∴ No. of bricks= 250 + (250 x 0.05)
= 250+12.5
=262.5 No’s
So, you will needing 263 number of bricks to construct 10 foot long, 6 foot height & 4.5 inch thick wall.
Likewise you can calculate the number of bricks for any dimension of the wall, procedure for calculation remains same.
On the link below you can find the video for this blog, watch it for a clear understanding & detailed explanation.






Good afternoon
Please send it in metres not inches.
Kind regards
On Sun, 26 Jan 2020, 8:19 AM we civil engineers, wrote:
> Kishan Mudavath posted: ” Assuming:- Brick size = 9”x4.5”x3” Thickness of > mortar = 0.39” Brick size with mortar= (9+0.39)x(4.5+0.39)x(3+0.39) > ” >
Good Wook and very helpful. Thanks