Quantity of Bricks:-
Assuming:-
•Brick size = 9”x4.5”x3”
•Thickness of wall = 9”
•Thickness of mortar = 0.39”
•Brick size with mortar= (9+0.39)x(4.5+0.39)x(3+0.39) = 9.39”x4.89”x3.39” •
No. of bricks = Volume of Brickwork/ Volume of 1 Brick with mortar
Volume of 1 Brick = (9/12)x(4.5/12)x(3/12)= 0.75’x0.375’x0.25’ = 0.070 CFT
Volume of 1 Brick with mortar = 0.783’x0.408’x0.283’=0.090 CFT.
Volume of Brickwork = 10’ x 6’ x 0.75’ = 45 Cubic Foot (CFT)
No. of bricks = Volume of Brickwork/ Volume of 1 Brick with Mortar
∴ No. of bricks = 45 CFT/ 0.090 CFT
= 500 No’s
Brick wastage–> 5 to 10 %
Consider 10% brick wastage,
∴ No. of bricks= 500 + (500 x 0.1)
= 550 No’s
Quantity of cement:-
Quantity of mortar = Quantity of brickwork – Volume of Bricks
Volume of bricks =0.070 CFT x 500 No’s = 35 CFT
Quantity of mortar = 45 – 35
= 10 CFT
Mix Ratio –> 1:5
Dry volume of mortar = Wet volume x (1+0.33) (33% of volume)
Dry Volume of mortar= 10 x 1.33 = 13.3 CFT
Consider 5% wastage of mortar.
Dry volume of mortar = 13.3 + (13.3 x 0.05) = 13.3+0.665 = 13.965 ≊ 14 CFT
Quantity of Cement = {(Dry Volume of mortar x Cement ratio) / (Sum of the ratio)}
∴Quantity of cement = (14 x 1) /(1+5)=2.333 CFT
Density of Cement = 1440 kg/m³
1 m³=35.3147 Cubic Feet (CFT)
∴ Quantity of Cement = 2.333/35.3147 = 0.066 m³
∴ Weight of Cement = 1440 x 0.066 = 95.04 Kg
1 bag of cement contains 50 kg of cement
∴ Number of bags = 95.04 Kg / 50 kg = 1.90 No’s (Say 2 No of bags)
Quantity of Sand:-
Cement : Sand :: 1:5
Quantity of Sand = Quantity of Cement x 5
∴ Quantity of Sand = 2.333 x 5= 11.665 CFT
1 m³=35.3147 Cubic Feet (CFT)
∴ Quantity of sand = 11.665/35.3147 = 0.330 m³
Density of sand = 1600 kg/m³
∴ Weight of the sand= 0.330 x 1600= 528 kg (0.528 tonnes)
From the link below you can find the video for this blog, watch it for a clear understanding & detailed explanation.
Dear sir please give me the no of bricks and cement bag number to construct 7.65*7.65*1.8 m and wall thickness is 0.23m
Early response in this regard is highly appreciated
1 brick 1kg sand 200g cemnt👍
Dear sir please give me the no of bricks and cement bag number to construct 7.65*7.65*1.8 m and wall thickness is 0.23m
Early response in this regard is highly appreciated
✔ Bricks required ≈ 6650 bricks
✔ Cement required ≈ 17 bags (for 1:6 mortar)
Thank you sir, how whould take and get trian me more ( to do my I T with you people?)
Thank you sir, how whould i get you to trian me more ( to do I T with you)?
Amazing, really well explained
Thank you
Thank You very much Sir.
….Can I have an online textbook containing all these calculations?
You can refer following books.
1. Estimating and Costing in Civil Engineering by BN Dutta
2. Estimating,Costing,Specification & Valuation In Civil Engineering By M Chakraborti https://amzn.to/4tduTT9
Best regards sir, pls how much rods is required to build 6 rooms self containe. Just the down stairs 12″14
How many bricks are required in a ladder of 24 steps if each step is 22cm x 24 cm x 2 feet.
Bricks required ≈ 400 to 420 bricks
In this question about for calculating quantity of different material or tools used in civil engineering, I want to ask you haw to make a software used in calculating those quality for easy way, like using achicad or autocad software, that’s my comment I currently studying in IPRC Ngoma in Rwanda cauntry, thank you.
if brick size 8.75″x4.25″x2.75″ than 10’ x 6’ x 0.75’ = 45 Cubic Foot (CFT) {calculate cement and sand}
Cement required ≈ 2 bags
Sand required ≈ 15 CFT